Module Three:
Distributive Property and
Factoring
Distributive Property
The distributive property involves multiplication along with addition and/or subtraction and is stated as follows:
a(b + c) = ab + ac
or
a(b – c) = ab – ac
Example 1. Simplify: 5x(4x
– 9)
Step 1. ![]()
Step 2. 20x2 – 45x
Example 2.
Simplify: 3(2x
+ y – 4)
Step 1. ![]()
Step 2. 6x + 3y – 12
Example 3.
Simplify: (x
– 3)(4x + 5)
Step 1. x(4x + 5) – 3(4x + 5)
Step 2. 4x2 + 5x – 12x – 15
Step 3. 4x2 – 7x – 15
Example 4.
Simplify: (2x
– 1)(3x – 4)
Step 1. 2x(3x – 4) – 1(3x – 4)
Step 2. 6x2 – 8x – 3x + 4
Step 3. 6x2 – 11x + 4
Example 5.
Simplify: (3a
– 7)(a + c)
Step 1. 3a(a + c) – 7(a + c)
Step 2. 3a2 + 3ac – 7a – 7c
or 3a2 + (3c – 7)a – 7c
Example 6.
Simplify: (5x
+ 2y)2
Step 1. (5x + 2y)(5x + 2y)
Step 2. 5x(5x + 2y) + 2y(5x + 2y)
Step 3. 25x2 + 10xy + 10xy + 4y2
Step 4. 25x2 + 20xy + 4y2
or 25x2 + 4y2 + 20xy
The following example is occasionally confused with the distributive property.
Example 7.
Simplify: (5x2y)3
Step 1. (5x2y) (5x2y) (5x2y)
Step 2. .![]()
Step 3. 125x6y3
Note that there is no addition or subtraction indicated within the parentheses, so the distributive property does not apply.
Factoring
For algebraic expressions where the distributive property is used in reverse, or undone, the resulting procedure is called factoring.
Example 8.
Factor: 20x2
– 45x
Using the result from Example 2, we will factor this expression showing that factoring means to express a quantity as a product of factors.
Step 1. The greatest common factor(GCF) is 5x.
Step 2. Rewrite the expression using the GCF
![]()
Step 3. Applying the distributive property in reverse we obtain
5x(4x – 9)
Example 9.
Factor: 8y3
+ 20y2 – 28y
Step 1. The GCF is 4y
Step 2. 4y · 2y2 + 4y · 5y – 4y · 7
Step 3. 4y(2y2 + 5y – 7)
Example 10.
Factor: 4x2
– 7x – 15
Note: refer to Example 3
Step 1. Set up 2 sets of parentheses
( )( )
Step 2. The factors of 4x2 are x, 4x or 2x,2x
The factors of – 15 are:
|
Factors |
|
Factors |
||
|
– 1 |
15 |
|
1 |
– 15 |
|
3 |
– 5 |
|
– 3 |
5 |
Step 3. Trying combinations of these factors in the parentheses results in the correct factors (x – 3)(4x + 5)
Example 11.
Factor: x2
– 5x – 24
Step 1. ( )( )
Step 2. The factors of x2 are x, x
The factors of – 24 are:
|
Factors |
|
Factors |
||
|
–1 |
24 |
|
1 |
– 24 |
|
2 |
– 12 |
|
– 2 |
12 |
|
– 3 |
8 |
|
3 |
– 8 |
|
4 |
– 6 |
|
– 4 |
6 |
Step 3. (x – 8)(x + 3)
Example 12.
Factor: 16x2 – 40x + 25
Step 1. ( )( )
Step 2. (4x – 5)(4x – 5)
Step 3. (4x – 5)2
In the preceding three examples, we factored trinomial expressions. In the next two examples, we review the method of factoring the difference of two squares.
Example 13.
Factor: 4x2 – 49
Step 1. ( + )( – )
Step 2. (2x + )(2x – )
Step 3. (2x + 7)(2x – 7)
Example 14.
Factor: 
Step 1. ( + )( – )
Step 2. ![]()
![]()
Step 3. ![]()
We will now review an example of an equation where one side is in factored form and the other side is equal to zero.
Example 15.
Is
0 a solution to either of the following equations?
A.
2y(y – 7) = 0
B. (y + 3)(y – 5) = 0
Recall that the product of two quantities equals zero if and only if at least one of the factors is zero.
For equation A, 2y(y – 7) = 0,
both 2y and y – 7 are factors. Set each factor equal to 0 and solve for y.
If y – 7 = 0 then y = 7.
If 2y = 0 then y = 0.
0 is a solution for equation A.
For equation B, (y + 3)(y – 5) = 0,
both y + 3 and y – 5 are factors.
If y + 3 = 0 then y = – 3.
If y – 5 = 0 then y = 5.
0 is not a solution for equation B.
Practice Problems
1. Simplify: – 6(z – 2k + 3)
Solution to problem 1:
– 6z + 12k – 18
2. Simplify: 8x( 4x5– 3x2)
Solution to problem 2:
32x6 – 24x3
3. Simplify: (8p + q)2
Solution to problem 3:
64p2 + 16pq + q2
4. Simplify: (– 4a2c3)2
Solution to problem 4:
16a4c6
5. Simplify: (3d + e)(2x – 5)
Solution to problem 5:
6dx – 15d + 2xe – 5e
6. Factor:
3y9 – 6y8 – 27y4
Solution to problem 6:
GCF = 3y4
3y4(y5 – 2y4 – 9)
7. Factor: x2 – 9xy + 20y2
Solution to problem 7:
(x – 5y)(x – 4y)
8. Factor: 81 – 25m2
Solution to problem 8:
Difference of two squares
(9 + 5m)(9 – 5m)

Solution to problem 9:
Difference of two squares
![]()